1.(1)=COUNTIF(B3:B10,"">10"")
={COUNT(0/(B3:B10>10))}
={SUM(N(3:B10>10))}"
(2). =SUM(COUNTIF(C3:C10,">="&{1500,3000})*{1,-1})
=COUNTIFS(C3:C10,">=1500",C3:C10,"<3000")
=INDEX(FREQUENCY(C3:C10,{1500,3000}),2)
2.={MMULT(TRANSPOSE((B19:B28=B19)*(C19:C28>5000)),ROW(19:28)^0)}
=SUMPRODUCT((B19:B28="事业部1")*(C19:C28>5000))
3.=SUMIFS(D33:D56,B33:B56,"*一*",C33:C56,"男")/COUNTIFS(B33:B56,"*一*",C33:C56,"男")
=AVERAGEIFS(D33:D56,B33:B56,"*一*",C33:C56,"男")
={AVERAGE(IF((MID(B33:B56,2,1)="一")*(C33:C56="男"),D33:D56))}
4.论述题
(1)用COUNTIF(A61:A70,A61:A70) 统计每个数值出现的次数
(2)用1/COUNTIF(A61:A70,A61:A70)如果重复数值是有1个,就有一个1/1, 有2个,就有一个1/2,其它数据依此类推.
(3)用SUM(1/COUNTIF(A61:A70,A61:A70)),一个1/1相加就是1,两个1/2相加也就是1.依此类推可以求出非重复项的个数.
也可以用=SUM(N(MATCH(A61:A70,A61:A70,)=ROW(61:70)-60))
=COUNT(1/FREQUENCY(MATCH(A61:A70,A61:A70,),MATCH(A61:A70,A61:A70,)))
=SUM(N(FREQUENCY(CODE(A61:A70),CODE(A61:A70))>0))
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