=LEFT(ADDRESS(1,COLUMN(),4),LEN(ADDRESS(1,COLUMN()))-3)
在2003中可到IV,2007中可到XFD
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公平 发表于 2010-5-29 20:59 =SUBSTITUTE(ADDRESS(1,COLUMN(),4),"1","")显示的是“M”
豆丁 发表于 2010-5-29 21:17 Function LH(k As Integer) LH = Split(Columns(k).Address(0, 0), ":")(0)End Function
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